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#1 |
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Prostate Examiner
I quoff fine wine at corkd.com
Join Date: Oct 2002
Location: good 'ole USA
Posts: 21,018
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You are on TV show,
there are 3 doors, behind 2 of them there is a goat, behind one is new BMW you opened the door and the host opens another door to show you it has a goat behind it. The host offers you to change your mind and pick up the other unopened door. Question: do you have 1) better chances by opening the other door? 2) worse chances by opening the other door 3) the same chances by opening the other door? ...and why?
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#2 |
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Cramming 3 people in a Room to Attend Show
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Join Date: Dec 2002
Location: New Orleans, LA
Posts: 5,306
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there are two answers to this problem.
ifit is a trick question, the fact that you said "a goat" would imply one goat, which if already revealed would mean your options are better. but if there was a goat behind the door you opened (not specified) then your odds would be 100% that the third door would hold a BMW, since both goats would be revealed. so that argument is all semantics. Say the door you opened was goatless, then it comes down to odds. the mathematical approach is you started with 66% odds of failure to start. eliminating one goat would mean your odds drop to 50% of failure, or a coin flip. at least thats my take
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#3 |
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Prostate Examiner
I quoff fine wine at corkd.com
Join Date: Oct 2002
Location: good 'ole USA
Posts: 21,018
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gotta be my bad English...
there are goats behind 2 out of 3 doors you haven't opened the door, you only indicated the door which you would like to open. sorry for misunderstanding the first time around
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#4 | |
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Prostate Examiner
I quoff fine wine at corkd.com
Join Date: Oct 2002
Location: good 'ole USA
Posts: 21,018
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Quote:
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#5 |
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Cramming 3 people in a Room to Attend Show
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oh shit i missed it completely.... one sec.
there is nothing specifying that a goat cannot be behind the same door as a goat. so the odds of failure are 5/6 for the goat with the BMW and 1/3 with the goat and BMW separate. so its a combination of odds problem now the host eliminates one out of each... since obviously the goat would not be in the door he opened, or the contetant would have already won. and the same goes for the door the contestant opened. so there is one door left with 3 possibilities. a goat, a BMW, or a goat and a BMWso it is 1/3 or 33%,much better odds. fucking trick questions
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#6 | |
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Cramming 3 people in a Room to Attend Show
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Quote:
anyway her odds are better
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#7 | |
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Banned
Join Date: Mar 2003
Posts: 539
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Quote:
You have a 66% chance of picking a goat on the first choice, the host then opens a door revealing a goat, cutting that down to a 66% chance of one of the doors containing a goat which, in actuality turns out to be a 50% chance you either have the goat or the BMW. |
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#8 |
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Prostate Examiner
I quoff fine wine at corkd.com
Join Date: Oct 2002
Location: good 'ole USA
Posts: 21,018
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Grimm,
I'll make it VERY simple: door #1 has goat behind it, door #2 has goat behind it, door #3 has BMW behind it. THIS you know. What you don't know is: which door is which. and you did NOT open the door on the first try, you only indicated which door you want to be opened, IOW, you don't know what's behind the door you have chosen!
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Cramming 3 people in a Room to Attend Show
Stop Lurking and start posting! Register now!
Join Date: Dec 2002
Location: New Orleans, LA
Posts: 5,306
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Quote:
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