Quote:
Originally posted by grimm@Nov 18 2004, 04:25 AM
oh shit i missed it completely.... one sec.
there is nothing specifying that a goat cannot be behind the same door as a goat.
so the odds of failure are 5/6 for the goat with the BMW and 1/3 with the goat and BMW separate. so its a combination of odds problem
now the host eliminates one out of each... since obviously the goat would not be in the door he opened, or the contetant would have already won. and the same goes for the door the contestant opened. so there is one door left with 3 possibilities. a goat, a BMW, or a goat and a BMWso it is 1/3 or 33%,much better odds.
fucking trick questions
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goat cannot be behind the same door as another goat, or the BMW, but that doest change the outcome. the revealing of the goat took us to 1/3 anyway, if and only if there were two goats in there, her odds would go to 100% choice as she had seen both goats and an empty door, so that doesnt matter.
anyway her odds are better