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grimm · 11-18-2004

oh shit i missed it completely.... one sec.

there is nothing specifying that a goat cannot be behind the same door as a goat.

so the odds of failure are 5/6 for the goat with the BMW and 1/3 with the goat and BMW separate. so its a combination of odds problem

now the host eliminates one out of each... since obviously the goat would not be in the door he opened, or the contetant would have already won. and the same goes for the door the contestant opened. so there is one door left with 3 possibilities. a goat, a BMW, or a goat and a BMWso it is 1/3 or 33%,much better odds.

fucking trick questions

11-18-2004	#5
grimm Cramming 3 people in a Room to Attend Show Stop Lurking and start posting! Register now! Join Date: Dec 2002 Location: New Orleans, LA Posts: 5,306	oh shit i missed it completely.... one sec. there is nothing specifying that a goat cannot be behind the same door as a goat. so the odds of failure are 5/6 for the goat with the BMW and 1/3 with the goat and BMW separate. so its a combination of odds problem now the host eliminates one out of each... since obviously the goat would not be in the door he opened, or the contetant would have already won. and the same goes for the door the contestant opened. so there is one door left with 3 possibilities. a goat, a BMW, or a goat and a BMWso it is 1/3 or 33%,much better odds. fucking trick questions __________________ Think horses, not zebras.